**Fibonacci**

Write a program , that prints all the Fibonacci numbers ,which are smaller than or equal to a number k(k≥2) ,which was entered by the user.

The Fibonacci numbers are a sequence of numbers,where then-th number of Fibonacci is defined as:

Fib(0)=0,

Fib(1)=1,

Fib(n)=Fib(n-1)+Fib(n-2) Usage :> Input of k:21 > Fibonacci numbers<=21:01123581321

**Solution-**

#include<iostream> using namespace std; int main (void) { int r=0,a=0,n,b=1,i,c; char redo; do { a=0; b=1; cout<<"enter the the value of n:"; cin>> n; if(n>100){ cout<<"enter some lessor value"<<endl; } else{ cout<<a<<endl; for (i=0;i<=n;i++) { c=a+b; a=b; b=c; cout<<"serial no."<<i+1<<"=="; cout<<a <<endl; } cout<<"enter y or Y to continue:"; cin>>redo; cout<<endl<<endl; } } while(redo=='y'||redo=='Y'); system("pause"); return 0; }

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C++ program Fibonacci series

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Great Work.. I saw One more easiest way to Write a C Program To Print Fibonacci Series

ReplyDeleteC++ Program to Generate Fibonacci series

ReplyDeleteFibonacci Series is in the form of 0, 1, 1, 2, 3, 5, 8, 13, 21,...... To find this series we add two previous terms/digits and get next term/number.